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2x^2+41x-115=0
a = 2; b = 41; c = -115;
Δ = b2-4ac
Δ = 412-4·2·(-115)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-51}{2*2}=\frac{-92}{4} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+51}{2*2}=\frac{10}{4} =2+1/2 $
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